User Tools

Differences

This shows you the differences between two versions of the page.

Link to this comparison view

Both sides previous revisionPrevious revision
Next revision
Previous revision
technical:ising1d [2022/10/29 14:09] – [Characteristic polynomial] chunchungtechnical:ising1d [2022/10/29 15:10] (current) – [Simple case 1: $J = 1$, $h = 0$] chunchung
Line 41: Line 41:
 ====Simple case 1: $J = 1$, $h = 0$==== ====Simple case 1: $J = 1$, $h = 0$====
 The eigenvalues become The eigenvalues become
-$$ \lambda_\pm = e^{\beta}\pm e^{-\beta}. $$+\begin{equation} \lambda_\pm = e^{\beta}\pm e^{-\beta}. \end{equation}
 The partition function is The partition function is
-$$ Z = \left(e^\beta+e^{-\beta}\right)^N+\left(e^\beta-e^{-\beta}\right)^N . $$+\begin{equation} Z = \left(e^\beta+e^{-\beta}\right)^N+\left(e^\beta-e^{-\beta}\right)^N . \end{equation}
  
 Generally, the average energy $U = \langle E\rangle$ can be calculated from the $\beta$-derivative of $-\log Z$: Generally, the average energy $U = \langle E\rangle$ can be calculated from the $\beta$-derivative of $-\log Z$:
-\begin{eqnarray*+\begin{align
-U & = \langle E\rangle \\ +U &= \langle E\rangle \notag \\ 
-& = Z^{-1} \sum_{\mathbf{s}} E e^{-\beta E} \\ +&= Z^{-1} \sum_{\mathbf{s}} E e^{-\beta E} \notag \\ 
-& = - Z^{-1} \frac{\partial}{\partial\beta} Z \\ +&= - Z^{-1} \frac{\partial}{\partial\beta} Z \notag \\ 
-& = - \frac{\partial}{\partial\beta}\log Z +&= - \frac{\partial}{\partial\beta}\log Z \\ 
-\end{eqnarray*}+&= \frac{N\left[\left(e^\beta+e^{-\beta}\right)^{N-1}\left(e^\beta-e^{-\beta}\right)+\left(e^\beta+e^{-\beta}\right)\left(e^\beta-e^{-\beta}\right)^{N-1}\right]}{\left(e^\beta+e^{-\beta}\right)^N+\left(e^\beta-e^{-\beta}\right)^N} \notag \\ 
 +&= N\frac{r+r^{N-1}}{1+r^N} 
 +\end{align} 
 +where $r = \left(e^\beta-e^{-\beta}\right)/\left(e^\beta+e^{-\beta}\right)<1$ is the ratio between the two eigenvalues.
  

This website uses cookies. By using the website, you agree with storing cookies on your computer. Also, you acknowledge that you have read and understand our Privacy Policy. If you do not agree, please leave the website.

More information